Reduction potential of ions are given below: E ^ =1.19 ~V E ^ =1.65 ~V E ^ =1.74 ~V The…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
Reduction potential of ions are given below:
\(\mathrm{E}^{\circ}=1.19 \mathrm{~V} \mathrm{E}^{\circ}=1.65 \mathrm{~V} \mathrm{E}^{\circ}=1.74 \mathrm{~V}\)
The correct order of their oxidising power is:
(Jee Main 2024)
\(\mathrm{E}^{\circ}=1.19 \mathrm{~V} \mathrm{E}^{\circ}=1.65 \mathrm{~V} \mathrm{E}^{\circ}=1.74 \mathrm{~V}\)
The correct order of their oxidising power is:
(Jee Main 2024)
- \(\mathrm{ClO}_{4}^{-}>\mathrm{IO}_{4}^{-}>\mathrm{BrO}_{4}^{-}\)
- \(\mathrm{BrO}_{4}^{-}>\mathrm{IO}_{4}^{-}>\mathrm{ClO}_{4}^{-}\)
- \(\mathrm{BrO}_{4}^{-}>\mathrm{ClO}_{4}^{-}>\mathrm{IO}_{4}^{-}\)
- \(\mathrm{IO}_{4}^{-}>\mathrm{BrO}_{4}^{-}>\mathrm{ClO}_{4}^{-}\)
Answer
(B) BrO _ 4 ^ - > IO _ 4 ^ - > ClO _ 4 ^ -
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