_ n _ r=1 ^ n 1 n e^ r n is :
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\lim _{n \rightarrow \infty} \sum_{r=1}^{n} \frac{1}{n} e^{\frac{r}{n}}\) is :
- \(\bar{e}\)
- \(e-1\)
- \(1-e\)
- \(e+1\)
Answer
(B) e-1
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