A liquid which is confined inside an adiabatic piston is suddenly taken from state 1 to…
Chemistry · JEE Advanced · NTA Exams — Chemical Thermodynamics
A liquid which is confined inside an adiabatic piston is suddenly taken from state 1 to state 2 by a single stage process. If the piston comes to rest at point 2 as shown. Then the enthalpy change for the process will be :
- \(\Delta \mathrm{H}=\frac{2 \gamma \mathrm{P}_{0} \mathrm{~V}_{0}}{\gamma-1}\)
- \(\Delta \mathrm{H}=\frac{3 \gamma \mathrm{P}_{0} \mathrm{~V}_{0}}{\gamma-1}\)
- ∆H = – P0 V0
- None of these
Answer
(C) ∆ H = – P 0 V 0
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