A solid A + B – has a body centred cubic structure. The distance of closest approach…
Chemistry · JEE Advanced · NTA Exams — Solid State
A solid A+ B– has a body centred cubic structure. The distance of closest approach between the two ions is 0.767 Å. The edge length of the unit cell is
- \(\frac{\sqrt{3}}{\sqrt{2}} \mathrm{pm}\)
- 142.2 pm
- \(\sqrt{2}\) pm
- 88.56 pm.
Answer
(D) 88.56 pm.
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