A certain simple harmonic vibrator of mass 0.1 kg has a total energy of 10 J. Its…

Physics · JEE Advanced · NTA Exams — Oscillations and Waves

1. \(\mathrm{A}=\sqrt{2} \mathrm{~cm}, \mathrm{f}=\frac{500}{\pi} \mathrm{~Hz}\)
2. \(A=\sqrt{2} \mathrm{~cm}, f=\frac{1000}{\pi} \mathrm{~Hz}\)
3. \(A=\frac{1}{\sqrt{2}} \mathrm{~cm}, f=\frac{500}{\pi} \mathrm{~Hz}\)
4. \(A=\frac{1}{\sqrt{2}} \mathrm{~cm}, f=\frac{1000}{\pi} \mathrm{~Hz}\)

Answer

(A) A = 2 ~cm , f = 500 ~Hz

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