Column–I Column–II (A) f (x + y) = f (x) + f (y) (P) log 3 x (B) f (xy) = f (x) + f (y)…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Column–I Column–II
(A) f (x + y) = f (x) + f (y) (P) log3 x
(B) f (xy) = f (x) + f (y) (Q) tan–1 x
(C) f (x + y) = f (x) . f (y) (R) 3x
(D) f (x) + f (y) = f \(\left(\frac{x+y}{1-x y}\right)\) (S) 3x
The Correct Matching is :
(A) f (x + y) = f (x) + f (y) (P) log3 x
(B) f (xy) = f (x) + f (y) (Q) tan–1 x
(C) f (x + y) = f (x) . f (y) (R) 3x
(D) f (x) + f (y) = f \(\left(\frac{x+y}{1-x y}\right)\) (S) 3x
The Correct Matching is :
- (A–P); (B–R); (C–S); (D–Q)
- (A–R); (B–P); (C–S); (D–Q)
- (A–Q); (B–S); (C–P); (D–R)
- (A–R); (B–S); (C–Q); (D–P)
Answer
(B) (A–R); (B–P); (C–S); (D–Q)
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