What is the equilibrium expression for the reaction: P 4 (s) + 5O 2 (g) ⇌ P 4 O 10 (s)
Chemistry · NEET · NTA Exams — Equilibrium
What is the equilibrium expression for the reaction:
P4(s) + 5O2 (g) ⇌ P4O10 (s)
- \(K_{C}=\frac{\left[P_{4} O_{10}\right]}{\left[P_{4}\right]\left[O_{2}\right]^{5}}\)
- \(K_{C}=\frac{\left[P_{4} O_{10}\right]}{5\left[P_{4}\right]\left[O_{2}\right]}\)
- KC = [O2]5
- \(K_{C}=\frac{1}{\left[O_{2}\right]^{5}}\)
Answer
(D) K_ C = 1 [O_ 2 ]^ 5
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