6.3g of oxalic acid dihydrate have been dissolved in water to obtain a 250 mL solution…
Chemistry · JEE Advanced · NTA Exams — Some Basic Concepts in Chemistry
6.3g of oxalic acid dihydrate have been dissolved in water to obtain a 250 mL solution. How much volume of 0.1 N NaOH would be required to neutralise 10 mL of this solutions ? (2001)
- 40 mL
- 20 mL
- 10 mL
- 4 mL
Answer
(A) 40 mL
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The reaction, 3 ClO ( aq )^ - ClO _ 3 ( aq )^ - +2 Cl ( aq )^ - is an example of (2001)
- One mole of a monoatomic real gas satisfies the equation P ( V – b ) = RT where b is a constant. The…
- Two non-reactive monoatomic ideal gases have their atomic masses in the ratio 2 : 3. The ratio of their…
- A gaseous mixture contains oxygen and nitrogen in the ratio of 1 : 4 by weight. Therefore, the ratio of their…
- The oxidation number of cobalt in K 3 [Co(NO 2 ) 6 ] is
- 1 gm Mg sample is treated with 125 ml 0.1 N HCl and the excess of HCl is neutralised by 50 ml 0.5 N NaOH…
- The given graph represents the variation of Z (compressibility factor = ) versus P , for three real gases A …
- The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing…
More Some Basic Concepts in Chemistry questions · Browse all practice questions