Two metallic plates of equal thicknesses and thermal conductivities K 1 and K 2 are put together face to face and a common plate is constructed, figure. The equivalent thermal conductivity will be:

Two metallic plates of equal thicknesses and thermal conductivities K 1 and K 2 are put…

Physics · JEE Main · NTA Exams — Thermodynamics

Two metallic plates of equal thicknesses and thermal conductivities K₁ and K₂ are put together face to face and a common plate is constructed, figure. The equivalent thermal conductivity will be:

\(\frac{\mathrm{K}_{1} \mathrm{~K}_{2}}{\mathrm{~K}_{1}+\mathrm{K}_{2}}\)
\(\frac{2 \mathrm{~K}_{1} \mathrm{~K}_{2}}{\mathrm{~K}_{1}+\mathrm{K}_{2}}\)
\(\frac{\mathrm{K}_{1}+\mathrm{K}_{2}}{2}\)
\[\frac{\left(K_{1}^{2}+K_{2}^{2}\right)^{3 / 2}}{2 K_{1} K_{2}}\]

Answer

(B) 2 ~K _ 1 ~K _ 2 ~K _ 1 + K _ 2

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Two metallic plates of equal thicknesses and thermal conductivities K 1 and K 2 are put…

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