A disc of radius r rolls on a horizontal ground with linear acceleration a and angular…
Physics · JEE Main · NTA Exams — Rotational Motion
A disc of radius r rolls on a horizontal ground with linear acceleration a and angular acceleration
as shown in figure. The magnitude of acceleration of point P shown in figure at an instant when its linear velocity is v and angular velocity is \(\boldsymbol{\omega}\) will be:


- \(\sqrt{(a+r \alpha)^{2}+\left(r \omega^{2}\right)^{2}}\)
- \(\frac{a r}{R}\)
- \(\sqrt{r^{2} \alpha^{2}+r^{2} \omega^{4}}\)
- \(\text { rα }\)
Answer
(A) (a+r )^ 2 + (r ^ 2 )^ 2
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