The potential energy of a particle varies with distance x from a fixed origin as y= A x x+B , where A and B are constants. The dimensions of AB are:

The potential energy of a particle varies with distance x from a fixed origin as y= A x…

Physics · NEET · NTA Exams — Physics and Measurement

The potential energy of a particle varies with distance x from a fixed origin as \(y=\frac{A \sqrt{x}}{x+B}\) , where A and B are constants. The dimensions of AB are:

[ML⁵^/²T ^-2]
[ML²T^-2]
[ML³^/²T^-2]
[ML⁷^/²T^-2]

Answer

(D) [ML 7 / 2 T -2 ]

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