There are n 1 photons of frequency v_ 1 in a beam of light. In a equally energetic beam…
Chemistry · JEE Main · NTA Exams — Atomic Structure
There are n1 photons of frequency \(v_{1}\) in a beam of light. In a equally energetic beam there are n2 photons of frequency \(v_{2}\). Then the correct relation is
- \(\frac{n_{1}}{n_{2}}=\frac{v_{1}}{v_{2}}\)
- \(\frac{n_{1}}{n_{2}}=1\)
- \(\frac{n_{1}}{n_{2}}=\frac{v_{2}}{v_{1}}\)
- \(\frac{n_{1}}{n_{2}}=\frac{v_{2}^{2}}{v_{1}^{2}}\)
Answer
(C) n_ 1 n_ 2 = v_ 2 v_ 1
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Light from a monochromatic source of wavelength, is incident normally on a small photo-sensitive surface of…
- In a multi-electron atom, which of the following orbitals described by the three quantum numbers will have…
- The energy of hydrogen atom in its ground state is -13.6 eV. The energy of the level corresponding to the…
- The wavelength of a spectral line for an electronic transition is inversely related to:
- Given below are two statements: Statement I: According to Bohr's model of hydrogen atom, the angular momentum…
- Which electronic configuration does not follow the Pauli’s exclusion principle ?
- A 3d-electron having s = +1/2 can have a magnetic quantum no :
- Which of the following is the correct plot for the probability density ^ 2 (r) as a function of distance ‘r’…
More Atomic Structure questions · Browse all practice questions