Find the value of _ 0 ^ ( 2 x- 2 x) d x
Physics · NEET · NTA Exams — Basic Mathematics for Physics
Find the value of \(\int_{0}^{\pi}(\cos 2 x-\sin 2 x) d x\)
- \(\frac{3}{2}\)
- \(\frac{1}{2}\)
- 0
- -1
Answer
(C) 0
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