If n_ 1 r N and ^ n-1 C_ r = [k^ 2 -3 ] ^ n c_ r+1 then k lies in the interval
Mathematics · JEE Main · NTA Exams — Permutations and Combinations
If \(n_{1} \mathrm{r} \in N\) and \({ }^{n-1} C_{r}\) \(=\left[k^{2}-3\right]{ }^{n} c_{r+1}\) then k lies in the interval
- \([-\sqrt{3}, \sqrt{3}]\)
- \((2, \infty)\)
- \([-\sqrt{3}, \infty]\)
- \((\sqrt{3}, 2]\)
Answer
(D) ( 3 , 2]
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