O ( ~g )+2 e ^ - O ^ 2- ( g ) ∆H = 744.7 kJ mol -1 . The positive value of ∆H is due to:
Chemistry · NEET · NTA Exams — Classification of Elements and Periodicity in Properties
\(\mathrm{O}(\mathrm{~g})+2 \mathrm{e}^{-} \rightarrow \mathrm{O}^{2-}(\mathrm{g})\) ∆H = 744.7 kJ mol-1. The positive value of ∆H is due to:
- Energy is needed to add 1e- to O
- Energy is required to add 1e- to \(0^{-}\)
- Energy is released to add 1e- to \(0^{-}\)
- None of these
Answer
(A) Energy is needed to add 1e - to O
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