An industrial fuel, ‘water gas’ which consists of a mixture of H 2 and CO can be made by…

Chemistry · JEE Advanced · NTA ExamsEquilibrium

An industrial fuel, ‘water gas’ which consists of a mixture of H2 and CO can be made by passing steam over red-hot carbon. The reaction is
\(\mathrm{C}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{~g}) \rightleftharpoons \mathrm{CO}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g}) ; \Delta \mathrm{H}=+131 \mathrm{~kJ}\) 
The yield of CO and H2 at equilibrium would be shifted to the product side by
  1. raising the relative pressure of steam
  2. adding hot carbon
  3. raising the temperature
  4. reducing the volume of the system

Answer

(A) raising the relative pressure of steam, (C) raising the temperature

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