A flake of glass (refractive index 1.5) is placed over one of the openings of a double…
Physics · JEE Advanced · NTA Exams — Optics
A flake of glass (refractive index 1.5) is placed over one of the openings of a double slit apparatus. The interference pattern displaces itself through seven successive maxima towards the side where the flake is placed. if wavelength of the diffracted light is \(\lambda=600 \mathrm{~mm}\), then the thickness of the flake is
- 2100 nm
- 4200 nm
- 8400 nm
- None of these
Answer
(C) 8400 nm
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