If P=(x, y), F_ 1 =(3,0), F_ 2 =(-3,0) and 16 x^ 2 +25 y^ 2 =400 , then P F_ 1 +P F_ 2…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

If \(P=(x, y), F_{1}=(3,0), F_{2}=(-3,0) \text { and } 16 x^{2}+25 y^{2}=400\), then \(P F_{1}+P F_{2}\) equals
  1. 8
  2. 6
  3. 10
  4. 12

Answer

(C) 10

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