Find the value of x for which the expansion 2+x (3-2 x)^ 2 is valid
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
Find the value of x for which the expansion \(\frac{2+x}{(3-2 x)^{2}}\) is valid
- \(|\mathbf{x}|<1\)
- \(|x|<\frac{3}{2}\)
- \(|\mathbf{x}|<0\)
- None of these
Answer
(B) |x|< 3 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If n>1 then (1+ x )^ n - n x -1 is divisible by
- Let (x+10)^ 5 +(x-10)^ 5 a =a_ a +a_ 1 x+a_ 2 x^ 2 + +a_ 5 a x^ 5 a , for all x R; then a_ 2 a_ n is equal to:
- Given below are two statements. STATEMENT - 1: If n ∈ N and 'n' is not a multiple of 3 and (1+x+x^ 2 )^ n = _…
- If n is not a multiple of 3, then the coefficient of x n in the expansion of _ r [1+x+x^ 2 ] is :
- The coefficient of the term independent of x in the expansion of [ x 3 + 3 2 x^ 2 ]^ 1 is :
- If (10)^ 9 +2(11)^ 1 (10)^ 1 +3(11)^ 2 (10)^ 7 + +10(11)^ 9 =k(10)^ 9 , then k is equal to :
- The greatest value of the term independent of x, as α varies over R, in the expansion of (x + x )^ 20 is :
- If (2+3 x)^ -5 expands in ascending powers of x , then x belongs to
More Binomial Theorem And Its Simple Applications questions · Browse all practice questions