A beam of beryllium nucleus ( z = 4) of kinetic energy 5.3 MeV is headed towards the…
Physics · Class 12 · CBSE — Atoms
A beam of beryllium nucleus (z = 4) of kinetic energy 5.3 MeV is headed towards the nucleus of gold atom (Z = 79). What is the distance of closest approach?
- 10.32 × 10–14 m
- 8.58 × 10–14 m
- 3.56 × 10–14 m
- 1.25 × 10–14 m
Answer
(B) 8.58 × 10 –14 m
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