One end of a spring of force constant k is fixed to a vertical wall and the other to a…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance \(x_{0}\) from the black. The spring is then compressed by \(2 x_{0}\) and released. The time taken to strike the wall is
- \(\frac{1}{6} \pi \sqrt{\frac{k}{m}}\)
- \(\sqrt{\frac{k}{m}}\)
- \(\frac{2 \pi}{3} \sqrt{\frac{m}{k}}\)
- \(\frac{\pi}{4} \sqrt{\frac{k}{m}}\)
Answer
(C) 2 3 m k
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