A deutron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 metre in…
Physics · JEE Main · NTA Exams — Magnetic Effects of Current and Magnetism
A deutron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 metre in a plane perpendicular to magnetic field \(\stackrel{\rightharpoonup}{\mathrm{B}}\). The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same \(\stackrel{\rightharpoonup}{\mathrm{B}}\) is
- 200 keV
- 100 keV
- 50 keV
- 25 keV
Answer
(B) 100 keV
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