Consider the following reaction _ 1 H ^ 2 + _ 1 H ^ 2 _ 2 He ^ 4 + Q If m ( 1 H 2 ) =…
Physics · JEE Main · NTA Exams — Atoms and Nuclei
Consider the following reaction
\({ }_{1} \mathrm{H}^{2}+{ }_{1} \mathrm{H}^{2} \longrightarrow{ }_{2} \mathrm{He}^{4}+\mathrm{Q}\)
If m (1H2) = 2.0141 u ; m (2He4) = 4.0024 u. The energy Q released (in MeV) in this fusion reaction is
\({ }_{1} \mathrm{H}^{2}+{ }_{1} \mathrm{H}^{2} \longrightarrow{ }_{2} \mathrm{He}^{4}+\mathrm{Q}\)
If m (1H2) = 2.0141 u ; m (2He4) = 4.0024 u. The energy Q released (in MeV) in this fusion reaction is
- 12
- 6
- 24
- 48
Answer
(C) 24
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