A 10 kg satellite circles earth once every 2 h in an orbit having a radius of 8000 km…
Physics · Class 12 · CBSE — Atoms
A 10 kg satellite circles earth once every 2 h in an orbit having a radius of 8000 km. Assuming that Bohr’s angular momentum postulate applies to a satellite just as it does to an electron in the hydrogen atom, then the quantum number of the orbit of satellite is
- 5.3 × 1040
- 5.3 × 1045
- 7.8 × 1048
- 7.8 × 1050
Answer
(B) 5.3 × 10 45
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The volume occupied by an atom is greater than the volume of the nucleus by a factor of about:
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by…
- From quantisation of angular momentum, one gets for hydrogen atom, the radius of the n th orbit as r_ n = (…
- If muonic hydrogen atom is an atom in which a negatively charged muon (μ) of mass about 207 m e revolves…
- The binding energy of a H-atom, considering an electron moving around a fixed nuclei (proton), is B=- m e^ 4…
- The impact parameter for an alpha particle approaching a target nucleus is maximum when the scattering angle…
- In an atom the ratio of radius of orbit of electron to the radius of nucleus is
- If n is the orbit number of the electron in a hydrogen atom, the correct statement among the following is