Distance between body centred atom and a corner atom in sodium (a = 4.225 A ^ o ) is
Chemistry · Class 12 · CBSE — Solutions
Distance between body centred atom and a corner atom in sodium (a = 4.225 \(\mathop {\text{A}}\limits^{\text{o}}\) ) is
- 2.99 \(\mathop {\text{A}}\limits^{\text{o}}\)
- 2.54 \(\mathop {\text{A}}\limits^{\text{o}}\)
- 3.66 \(\mathop {\text{A}}\limits^{\text{o}}\)
- 3.17 \(\mathop {\text{A}}\limits^{\text{o}}\)
Answer
(C) 3.66 A ^ o
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