The geometry around boron in the product 'B' formed from the following reaction is BF 3 +…
Chemistry · JEE Main · NTA Exams — p-Block Elements
The geometry around boron in the product 'B' formed from the following reaction is
BF3 + NaH \(\xrightarrow{450 \mathrm{~K}}\) A + NaF
A + NMe3 → B (JEE Main 2022)
BF3 + NaH \(\xrightarrow{450 \mathrm{~K}}\) A + NaF
A + NMe3 → B (JEE Main 2022)
- Trigonal planar
- Tetrahedral
- Pyramidal
- Square planar
Answer
(B) Tetrahedral
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