Order of magnitude of density of Uranium nucleus is ( m _ p =1.67 10^ -27 ~kg )
Physics · NEET · NTA Exams — Atoms and Nuclei
Order of magnitude of density of Uranium nucleus is \(\left(\mathrm{m}_{\mathrm{p}}=1.67 \times 10^{-27} \mathrm{~kg}\right)\)
- \(10^{20} \mathrm{~kg} / \mathrm{m}^{3}\)
- \(10^{17} \mathrm{~kg} / \mathrm{m}^{3}\)
- \(10^{14} \mathrm{~kg} / \mathrm{m}^{3}\)
- \(10^{11} \mathrm{~kg} / \mathrm{m}^{3}\)
Answer
(B) 10^ 17 ~kg / m ^ 3
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