Given that, H _ f ^ 0 (CO 2 , g) = – 393.509 kJ mol –1 , H _ f ^ 0 (H 2 O, l ) = –…
Chemistry · JEE Advanced · NTA Exams — Chemical Thermodynamics
Given that,
\(\Delta \mathrm{H}_{\mathrm{f}}^{0}\)(CO2, g) = – 393.509 kJ mol–1,
\(\Delta \mathrm{H}_{\mathrm{f}}^{0}\)(H2O, l ) = – 285.830 kJ mol–1,
\(\Delta \mathrm{H}_{\mathrm{f}}^{0}\)(C2H5OH, l) = – 277.800 kJ mol–1.
Calculate the ∆Hº (combustion) of liquid ethanol. The following is the required reaction.
C2H5OH (l ) + 3O2 (g) → 2CO2 (g) + 3H2O (l )
\(\Delta \mathrm{H}_{\mathrm{f}}^{0}\)(CO2, g) = – 393.509 kJ mol–1,
\(\Delta \mathrm{H}_{\mathrm{f}}^{0}\)(H2O, l ) = – 285.830 kJ mol–1,
\(\Delta \mathrm{H}_{\mathrm{f}}^{0}\)(C2H5OH, l) = – 277.800 kJ mol–1.
Calculate the ∆Hº (combustion) of liquid ethanol. The following is the required reaction.
C2H5OH (l ) + 3O2 (g) → 2CO2 (g) + 3H2O (l )
- – 1366.82 kJ mol–1
- – 278.82 kJ mol–1
- – 2264.66 kJ mol–1
- – 1155.78 kJ mol–1
Answer
(A) – 1366.82 kJ mol –1
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