The values of m for which the equation 2 x^ 2 +m x y+3 y^ 2 -5 y-2=0 can be expressed as…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The values of \(m\) for which the equation \(2 x^{2}+m x y+3 y^{2}-5 y-2=0\) can be expressed as the product of two linear factors are :
- \(\pm 7\)
- \(\pm 5\)
- \(\pm 4\)
- \(\pm 1\)
Answer
(A) 7
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The equation ax 2 + by 2 + 2hxy + 2gx + 2fy + c = 0 represents a circle only if
- Any point on the parabola whose focus is (0, 1) and the directrix is x + 2 = 0 is given by
- The number of values of c such that the straight line y=4 x+c touches the curve x^ 2 4 +y^ 2 =1 is,
- An ellipse has its centre at (1, –1) and semi major axis equal to 8. If this ellipse passes through the point…
- The values of 'm' for which a line with slope m is common tangent to the hyperbola x^ 2 a^ 2 - y^ 2 b^ 2 =1(a…
- Let s= (x, y) R^ 2 : y^ 2 1+r - x^ 2 1-r =1 ; r 1 . Then S represents
- Centre of the circle x 2 + y 2 – 2x + 4y + 1 = 0 is –
- The co-ordinates of the foot of perpendicular from (a, 0) on the line y = mx + a ~m are
More Co-ordinate Geometry questions · Browse all practice questions