The equation of common tangent to the curves y^ 2 =16 x and x y=-4 , is:
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of common tangent to the curves \(y^{2}=16 x\) and \(x y=-4\), is:
- \(x-y+4=0\)
- \(x+y+4=0\)
- \(x-2 y+16=0\)
- \(z x-y+z=0\)
Answer
(A) x-y+4=0
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