Consider the chemical reaction, N 2 (g) + 3H 2 (g) → 2NH 3 (g). The rate of this reaction…

Chemistry · NEET · NTA Exams — Chemical Kinetics

Consider the chemical reaction, N₂(g) + 3H₂(g) → 2NH₃(g). The rate of this reaction can be expressed in terms of derivative of concentration of N₂(g), H₂(g) of NH₃(g). Identify the correct relationship amongst the rate expressions:

Rate = \(-\frac{d\left[N_{2}\right]}{d t}=-\frac{1}{3} \frac{d\left[H_{2}\right]}{d t}=\frac{1}{2} \frac{d\left[N H_{3}\right]}{d t}\)
Rate = \(\frac{d\left[\mathrm{~N}_{2}\right]}{d t}=-3 \frac{d\left[\mathrm{H}_{2}\right]}{d t}=\frac{2 d\left[\mathrm{NH}_{3}\right]}{d t}\)
Rate = \(\frac{d\left[N_{2}\right]}{d t}=\frac{1}{3} \frac{d\left[H_{2}\right]}{d t}=\frac{1}{2} \frac{d\left[N H_{3}\right]}{d t}\)
Rate = \(-\frac{d\left[N_{2}\right]}{d t}=-\frac{d\left[H_{2}\right]}{d t}=\frac{d\left[N H_{3}\right]}{d t}\)

Answer

(A) Rate = - d [N_ 2 ] d t =- 1 3 d [H_ 2 ] d t = 1 2 d [N H_ 3 ] d t

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Consider the chemical reaction, N 2 (g) + 3H 2 (g) → 2NH 3 (g). The rate of this reaction…

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