The equation 2 sin 2 x 2 . cos 2 x = x + 1 x , 0 < x < 2 has
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The equation 2 sin2 \(\frac{x}{2}\). cos2 x = x + \(\frac{1}{x}\), 0 < x < \(\frac{\pi}{2}\) has
- one real solution
- no real solution
- infinitely many real solutions
- none of these
Answer
(B) no real solution
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let A = x R : x is not a positive integer . Define a function f : A → R as f(x)= 2 x x-1 , then f is:
- Let f(x) be a function given by f(x)= x^ 2 +1 [x] for all x ∈ [1, 4), where [.] denotes the greatest integer…
- The function f(x)= [ (x+ x^ 2 +1 ) ] is:
- Solve [ x 2 ]+ [ x 3 ]= 5 x 6 .
- If 5(x)=x+[x] and [x]- x = 1 2 (where (x) and [ x ] are fractional and integral part of x ), then x is :
- If f(x+y, x-y)=x y . then the arithmetic mean of f(x, y) and f(y, x) is
- Find the domain of the function f(x)= _ 2 (x+3) x^ 2 +3 x+2
- Let f(x)=x^ 2 , x R . For any A R, define g(A) = x R : f(x) A . If S = [0, 4], then which one of the…
More Sets, Relations and Functions questions · Browse all practice questions