Compound A (molecular formula C 3 H 8 O) is treated with acidified potassium dichromate…
Chemistry · JEE Advanced · NTA Exams — Aldehydes and Ketones
Compound A (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product B (molecular formula C3H6O). B forms a shining silver mirror on warming with ammonical silver nitrate. B when treated with an aqueous solution of H2NCONHNH2 and sodium acetate gives a product C. Identify the structure of C. (2002)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{N} . \mathrm{NHCONH}_{2}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{N} . \mathrm{CONHNH}{ }_{2}\)
Answer
(A) CH _ 3 CH _ 2 CH = N . NHCONH _ 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by…
- Clemmensen reduction involves > C = O to > CH 2 in presence of
- Which of the following compounds undergo aldol condensation?
- The reagent that gives an orange coloured precipitate with acetaldehyde
- An organic compound ‘A’ has the molecular formula C 3 H 6 O. It undergoes iodoform test. When saturated with…
- When a nucleophile encounters a ketone, the site of attack is
- A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by…
- Which of the following forms of an enol to the greatest extent ?
More Aldehydes and Ketones questions · Browse all practice questions