Light of two different frequencies whose photons have energies 1 eV and 2.5 eV…
Physics · JEE Main · NTA Exams — Atoms and Nuclei
Light of two different frequencies whose photons have energies 1 eV and 2.5 eV successively illuminate a metal of work function 0.5 eV. The ratio of the maximum speeds of the emitted electrons will be
- 1 : 5
- 1 : 4
- 1 : 2
- 1 : 1
Answer
(C) 1 : 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The ratio of the energies of the hydrogen atom in the first to the second excited state
- The de-Broglie wavelength of a molecule of thermal energy k B T (k B = Boltzmann constant and T = absolute…
- If radius of the _ 13 ^ 27 Al nucleus is estimated to be 3.6 fermi, then the radius of _ 52 ^ 125 Te nucleus…
- The binding energy per nucleon of 16 O is 7.97 MeV and that of 17 O is 7.75 MeV. The energy in MeV required…
- C -14 undergoes B-decay. _ 5 ^ 14 C _ 7 ^ 14 ~N + _ -1 ^ 5 e . If 1 × 10 11 atoms of carbon disintegrate per…
- In the nuclear reaction, _ 1 ^ 2 H + _ 1 ^ 2 H 1 2 He + 1 n n , if the binding energy of deuteron is 2.23 MeV…
- The anode voltage of a photocell is kept fixed. The wavelength λ of the light falling on the cathode is…
- A nuclear transformation is denoted by X ( n , ) _ 3 ^ 7 Li . Which of the following is the nucleus of…
More Atoms and Nuclei questions · Browse all practice questions