The velocity of a particle moving along x–axis is given as v = x2 – 5x + 4 (in m/s) where…
Physics · JEE Advanced · NTA Exams — Kinematics
The velocity of a particle moving along x–axis is given as v = x2 – 5x + 4 (in m/s) where x denotes the x–coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity of particle is zero?
- 0 m/s2
- 2 m/s2
- 3 m/s2
- none of these
Answer
(A) 0 m/s2
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