Two bodies M and N of equal masses are suspended from two separate massless springs of…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
Two bodies M and N of equal masses are suspended from two separate massless springs of force constants \(k_{1}\) and \(k_{2}\) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude M to that of N is
- \(\frac{k_{1}}{k_{2}}\)
- \(\sqrt{\frac{k_{1}}{k_{2}}}\)
- \(\frac{k_{2}}{k_{1}}\)
- \(\sqrt{\frac{r_{2}}{k_{1}}}\)
Answer
(D) r_ 2 k_ 1
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