A knife–edge divides a sonometer wire into two parts. The fundamental frequencies of the…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
A knife–edge divides a sonometer wire into two parts. The fundamental frequencies of the two parts are f1 and f2. The fundamental frequency of the sonometer wire when the knife–edge is removed will be
- f1 + f2
- \(\frac{1}{2}\left(f_{1}+f_{2}\right)\)
- \(\sqrt{f_{1} f_{2}}\)
- \(\frac{f_{1} f_{2}}{f_{1}+f_{2}}\)
Answer
(D) f_ 1 f_ 2 f_ 1 +f_ 2
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