In the following reaction sequence. C _ 6 H _ 5 Br [523 ~K ] CuCN / Pyridine X [ Boil ]…
Chemistry · JEE Main · NTA Exams — Organic Compounds Containing Oxygen
In the following reaction sequence.
\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Br} \xrightarrow[523 \mathrm{~K}]{\mathrm{CuCN} / \text { Pyridine }} \mathrm{X} \xrightarrow[\text { Boil }]{\text { Dil. } \mathrm{H}_{2} \mathrm{SO}_{4}} \mathrm{Y}\)
The product Y is
\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Br} \xrightarrow[523 \mathrm{~K}]{\mathrm{CuCN} / \text { Pyridine }} \mathrm{X} \xrightarrow[\text { Boil }]{\text { Dil. } \mathrm{H}_{2} \mathrm{SO}_{4}} \mathrm{Y}\)
The product Y is
- Benzonitrile
- Benzene
- Benzoic acid
- Benzamide
Answer
(C) Benzoic acid
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