The trajectory of a projectile in a vertical plane is y = ax – bx2, where a and b are…
Physics · JEE Advanced · NTA Exams — Kinematics
The trajectory of a projectile in a vertical plane is
y = ax – bx2, where a and b are constants and x and y are respectively horizontal and vertical distance of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection from the horizontal are
y = ax – bx2, where a and b are constants and x and y are respectively horizontal and vertical distance of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection from the horizontal are
- \(\frac{b^{2}}{2 a}, \tan ^{-1}(b)\)
- \(\frac{a^{2}}{b}, \tan ^{-1}(2 a)\)
- \(\frac{a^{2}}{4 b}, \tan ^{-1}(a)\)
- \(\frac{2 \mathrm{a}^{2}}{\mathrm{~b}}, \tan ^{-1}(\mathrm{a})\)
Answer
(C) a^ 2 4 b , ^ -1 (a)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If are non coplanar unit vectors such that then the angle between a ext and b is
- A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The displacement of the stone…
- Let v and a denote the velocity and acceleration respectively of a particle moving in a circular path then,
- If the vectors a , b and or the sides BC , CA and AB respectively of a triangle ABC , then
- A particle of mass m is moving in the xy -plane such that its velocity at a point ( x , y ) is given as v =…
- Two small particles of equal masses start moving in opposite directions from a point A in a horizontal…
- A rocket is fired upwards from earth’s surface such that it creates an acceleration of 20 ~ms ^ -2 . If after…
- A drag racing car starts from rest at t = 0 and moves along a straight line with velocity given by v = bt2…