The degree of dissociation (α) of a weak electrolyte, A x B y is related to van't Hoff…
Chemistry · NEET · NTA Exams — Solutions
The degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression:
- \(\mathbf{z}=\frac{i-1}{\mathbf{x}+\mathbf{y}+1}\)
- \(\mathbf{x}=\frac{\mathbf{x}+\mathbf{y}-1}{i-1}\)
- \(\mathbf{x}=\frac{\mathbf{x}+\mathbf{y}+1}{i-1}\)
- \(\mathbf{z}=\frac{i-1}{(\mathbf{x}+\mathbf{y}-1)}\)
Answer
(A) z = i-1 x + y +1
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