If m is the minimum value of k for which the function f(x)=x k x-x^ 2 is increasing in…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If m is the minimum value of k for which the function \(f(x)=x \sqrt{k x-x^{2}}\) is increasing in the interval [0, 3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to:
- \((5,3 \sqrt{6})\)
- \((4,3 \sqrt{3})\)
- \((4,3 \sqrt{2})\)
- \((3,3 \sqrt{3})\)
Answer
(B) (4,3 3 )
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