Power dissipated in an L-C-R series circuit connected to an AC source of emf E is

Power dissipated in an L-C-R series circuit connected to an AC source of emf \(E\) is

\(\frac{\epsilon^{2} R}{\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}\)
\(\frac{\epsilon^{2} \sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}{R}\)
\(\frac{\epsilon^{2}\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}{R}\)
\(\frac{\epsilon^{2}}{\sqrt{R^{2}+\left(L \omega-\frac{1}{C u}\right)^{2}}}\)

Answer

(A) ^ 2 R [R^ 2 + (L - 1 C )^ 2 ]

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