A car of mass m is taking a circular turn of radius ‘r’ on a frictional level road with a…

Physics · JEE Main · NTA ExamsRotational Motion

A car of mass m is taking a circular turn of radius ‘r’ on a frictional level road with a speed v. In order that the car does not skid-
Where ‘µ’ is coefficient of friction
  1. \(\frac{\mathrm{mv}^{2}}{\mathrm{r}}\) µmg
  2. \(\frac{\mathrm{mv}^{2}}{\mathrm{r}}\) µmg
  3. \(\frac{\mathrm{mv}^{2}}{\mathrm{r}}\) = µmg
  4. \(\frac{\mathrm{v}}{\mathrm{r}}\) = µmg

Answer

(B) mv ^ 2 r ≤ µ mg

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