The correct stability order of the resonance structures is: H _ 2 C = + N = N ; H _ 2 + C…
Chemistry · NEET · NTA Exams — Chemical Bonding and Molecular Structure
The correct stability order of the resonance structures is:
\(\mathrm{H}_{2} \mathrm{C}=\stackrel{+}{\mathrm{N}}=\overline{\mathrm{N}} ; \mathrm{H}_{2} \stackrel{+}{\mathrm{C}}-\mathrm{N}=\overline{\mathrm{N}} ; \mathrm{H}_{2} \overline{\mathrm{C}}-\stackrel{+}{\mathrm{N}} \equiv \mathrm{N} ; \mathrm{H}_{2} \overline{\mathrm{C}}-\mathrm{N}=\stackrel{+}{\mathrm{N}}\) (i) (ii) (iii) (iv)\)
- (I) > (II) > (IV) > (III)
- (I) > (III) > (II) > (IV)
- (II) > (I) > (III) > (IV)
- (III) > (I) > (IV) > (II)
Answer
(A) (I) > (II) > (IV) > (III)
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