If x [0, 2 ], the number of solutions of the equation, sin 7x + sin 4x + sin x = 0 is :
Mathematics · JEE Advanced · NTA Exams — Trigonometry
If \(\mathrm{x} \in\left[0, \frac{\pi}{2}\right],\) the number of solutions of the equation,
sin 7x + sin 4x + sin x = 0 is :
sin 7x + sin 4x + sin x = 0 is :
- 3
- 5
- 6
- None
Answer
(B) 5
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