If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their…
Chemistry · JEE Main · NTA Exams — Solutions
If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nA, nB and nC, mole fraction of C in the solution is:
(Jee Main 2024)
(Jee Main 2024)
- \(\frac{n_{C}}{n_{A} \times n_{B} \times n_{C}}\)
- \(\frac{n_{C}}{n_{A}+n_{B}+n_{C}}\)
- \(\frac{n_{C}}{n_{A}-n_{B}-n_{C}}\)
- \(\frac{n_{C}}{n_{A}+n_{B}}\)
Answer
(B) n_ C n_ A +n_ B +n_ C
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