The position vector of a particle is given as i = ( t ^ 2 -4 t +6 ) i + ( t ^ 2 ) j The…
Physics · JEE Advanced · NTA Exams — Kinematics
The position vector of a particle is given as \(\overline{\mathrm{i}}=\left(\mathrm{t}^{2}-4 \mathrm{t}+6\right) \hat{\mathrm{i}}+\left(\mathrm{t}^{2}\right) \hat{\mathrm{j}}\) The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to
- 1 sec
- 2 sec
- 1.5 sec
- not possible
Answer
(A) 1 sec
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