The equation Im ( i z-2 z-i )+1=0, z G, z i . represents a part of a circle having radius…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
The equation Im \(\left(\frac{i z-2}{z-i}\right)+1=0, z \in G, z \neq i\). represents a part of a circle having radius equal to:
- 1
- 2
- \(\frac{3}{4}\)
- \(\frac{1}{2}\)
Answer
(A) 1
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If z 1 and z 2 are two non-zero complex numbers such that |z 1 + z 2 | = |z 1 | + |z 2 |, and arg z 1 – arg z…
- For real parameter t, the locus of the complex number z= (1-t^ 2 )+i 1+t^ 2 in the complex plane is
- If a, b, c are distinct positive real numbers and a 2 + b 2 + c 2 = 1, then ab + bc + ac is
- The number of real roots of the equation, e^ 4 x +e^ 3 x -4 e^ 2 x +e^ x +1=0
- If is an imaginary cube root of unity, then (1+ - ^ 2 )^ 2 equals
- Suppose z 1 , z 2 , z 3 are the vertices of an equilateral triangle inscribed in the circle |z| = 2. If z 1 =…
- For a < 0 determine all real roots of equation x^ 2 -2 a|x-a|-3 a^ 2 =0 .
- If α and β be the roots of the equation x^ 2 -7 x+2=0 , then the least value of n for which ( x )^ n =1 is:
More Complex Numbers and Quadratic Equations questions · Browse all practice questions