What is the maximum acceleration of the particle doing the SHM y=2 [ t 2 + ], where y is…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
What is the maximum acceleration of the particle doing the SHM
\(y=2 \sin \left[\frac{\pi t}{2}+\phi\right],\) where y is in cm.
\(y=2 \sin \left[\frac{\pi t}{2}+\phi\right],\) where y is in cm.
- \(\frac{\pi}{2} \mathrm{~cm} / \mathrm{s}^{2}\)
- \(\frac{\pi^{2}}{2} \mathrm{~cm} / \mathrm{s}^{2}\)
- \(\frac{\pi}{4} \mathrm{~cm} / \mathrm{s}^{2}\)
- \(\frac{\pi^{2}}{4} \mathrm{~cm} / \mathrm{s}^{2}\)
Answer
(B) ^ 2 2 ~cm / s ^ 2
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