The valency of carbon is generally 4, but its oxidation state may be -4, -2, 0, 2, -1…
Chemistry · JEE Advanced · NTA Exams — Some Basic Concepts in Chemistry
The valency of carbon is generally 4, but its oxidation state may be -4, -2, 0, 2, -1 etc. In the compounds containing C, H and O, the oxidation number of C is calculated as
Oxidation number of C = \(\frac{2 \mathrm{n}_{\mathrm{O}}-\mathrm{n}_{\mathrm{H}}}{\mathrm{n}_{\mathrm{C}}}\)
where nO, nH, nC are the number of oxygen, hydrogen, and carbon atoms, respectively.
In which of the following compounds is the oxidation state of C highest?
- HCOOH
- HCHO
- CH3OH
- CH4
Answer
(A) HCOOH
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In a metal deficient oxide sample, M x Y 2 O 4 (M and Y are metals), M is present in both +2 and +3 oxidation…
- Two non-reactive monoatomic ideal gases have their atomic masses in the ratio 2 : 3. The ratio of their…
- Assertion (A): In the titration of Na 2 CO 3 with HCl using methyl orange indicator, the volume required at…
- An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to…
- The number of moles of KMnO 4 that will be needed to react with one mole of sulphite ion in acidic solution…
- A crystalline hydrated salt on being rendered anhydrous loses 45.6% of its weight. The percentage composition…
- The oxidation number of phosphorus in Ba(H 2 PO 2 ) 2 is
- Assertion : Equivalent volume of H 2 is 11.2 L at 1 atm and 273 K. Reason : 1/2 mole H 2 has produced when 1…
More Some Basic Concepts in Chemistry questions · Browse all practice questions